Perimeter of Rectangle

Perimeter = length + width + length + width

OR

Perimeter = 2 × length + 2 × width

For a square with side length *s*, the perimeter is equal to 4*s*.

Opposite sides of a rectangle are congruent.

Use the given information to set up an equation and solve for the perimeter.

For the equation, use the sum of the sides, or use two times length plus two times width.

Perimeter | = | length | + | length | + | width | + | width |

| = | 25 feet | + | 25 feet | + | 15 feet | + | 15 feet |

| = |
80 feet | | | | |

**OR**

Perimeter | = | (2 × length) | + | (2 × width) |

| = | (2 × 25 feet) | + | (2 × 15 feet) |

| = | 50 feet | + | 30 feet |

| = | 80 feet | | |

The perimeter of the rectangle is 80 feet.

Use the given information to set up an equation and solve for the width.

For the equation, use the sum of the sides, or use two times length plus two times width.

Perimeter | = | length | + | length | + | width | + | width |

60 feet | = | 20 feet | + | 20 feet | + | width | + | width |

60 feet | = |
40 feet | + | width | + | width |

60 feet | = |
40 feet | + | 10 feet | + | 10 feet |

**OR**

Perimeter | = | (2 × length) | + | (2 × width) |

60 feet | = | (2 × 20 feet) | + | (2 × width) |

60 feet | = | 40 feet | + | (2 × width) |

60 feet | = | 40 feet | + | 20 feet |

60 feet | = | 40 feet | + | (2 × 10 feet) |

The width of the rectangle is 10 feet.