Area of Triangle = $\frac{1}{2}$ × base × height

Area of Parallelogram = base × height

Area of Trapezoid = $\frac{1}{2}$(base_{1} + base_{2}) × height

Use the formula for the area of a parallelogram.

The height of a parallelogram is the perpendicular distance between either of the two sets of parallel sides.

So, the height is 3 cm, not 3.1 cm.

Area | = | *bh* |

| = | (6.5 cm)(3 cm) |

| = | 19.5 cm^{2} |

Use the formula for the area of a trapezoid.

The bases are the sides which are parallel.

The height is the perpendicular distance between the bases.

Area | = | $\frac{1}{2}$(*b*_{1} + *b*_{2})*h* |

| = | $\frac{1}{2}$(5.8 cm + 6.6 cm)(3 cm) |

| = | $\frac{1}{2}$(12.4 cm)(3 cm) |

| = | $\frac{1}{2}$(37.2 cm^{2}) |

| = | 18.6 cm^{2} |