The area of a triangle is one-half times the base times the height.
Examine the areas of both figures.
Areafigure 1 | = | ab |
|
Areafigure 2 | = | (ka)(kb) |
| = | kk(ab) |
| = | k2(Areafigure 1) |
So, the area of the new rectangle is 9 times the area of the original rectangle.