Area Rectangle = length × width

Area Triangle = $\frac{1}{2}$(base)(height)

Area Parallelogram = base × height

Area Trapezoid = $\frac{1}{2}$(base_{1} + base_{2})(height)

Area Circle = $\text{\pi}$*r*^{2}

First, find the area of each figure. Then, find the sum of those areas.

Area_{TRI} | = | $\frac{1}{2}$(base)(height) |

| = | $\frac{1}{2}$(16 cm)(13.9 cm) |

| = | 111.2 sq cm |

Area_{TRAP} | = | $\frac{1}{2}$(base_{1} + base_{2})(height) |

| = | $\frac{1}{2}$(33 cm + 42 cm)(16 cm) |

| = | 600 sq cm |

Area_{PARA} | = | base × height |

| = | (42 cm)(10 cm) |

| = | 420 sq cm |

Now, add the areas.

111.2 sq cm + 600 sq cm + 420 sq cm = 1,131.2 sq cm